I just someone to check my work, i have already done all of them but there is missing stuff i didn’t solve FOR Lab one what i want On page 7i need Part A : single melting point determination of unk


I just someone to check my work, i have already done all of them but there is missing stuff i didn’t solve 

FOR Lab one 

what i want 

On page 7i need Part A : single melting point determination of unknown sample  Table 

Page 8 all page, page 9all pages, page 10nothing.

And check every thing i solve

Experiment 1 Melting Point Observations

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Appearance of Unknown 350-1-A-1 -dull white powder

Appearance of Unknown 350-1-B-1 -dull white powder

Part A

packing of tube accomplished using a drop tube.

Amount of compound in melting point (mp) tube = 1 mm

Observations during mp = (see lab manual for a time lapse of step observed)

Temperatures recorded = 68.2-69.1 C

Part B

50:50 mixture created and mixed by mortar and pestle -dull white powder

packing of tube accomplished using a drop tube.

Amount of compound in mp tubes = 1 mm

Observations during mp = (see lab manual for recording of the time lapse of step observed)

Temperatures recorded = 1.B.1 alone = 106.1-106.8 C

mixed mp of 1.B.1 mixed with 4-nitrobenzaldehyde = 106.1-106.8 C

mixed mp of 1.B.1 mixed with 2-methylbenzoic acid = 93.0 – 98.5 C

therefore 1.B.1 id is 4-nitrobenzaldehyde

Experiment 2 Recrystallization Observations

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pages 14, 15, 16, 17 

and check the rest of the pages if i solve it right

and check everything i solve

Appearance of Impure Acetanilide? -dull white powder with some dark flecks

Amt weighed = 5.00g

Appearance of solvent selected = distilled water = clear and colorless

Volume of solvent used to dissolve the impure acetanilide = 50 mL

Appearance before charcoal addition = clear/colorless solution with white pptte on bottom of flask

Appearance after charcoal addition = clear/colorless solution with black charcoal powder throughout

and white pptte on bottom of flask

Appearance after gravity filtration = black charcoal powder on filter paper, filtrate = clear and

colorless

Appearance after cool down = crystals formed after 5 minutes, white shiny flakes growing in flask

Appearance of final purified acetanilide – white shiny flakes

Yield of final purified acetanilide = 2.98 g

mp of final purified acetanilide = 113-3-114.0 C

mixed mp of purified acetanilide + mp standard = 113-114 C.

Experiment 3 Distillation Observations

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pages 21,22,23,24 

 there a missing stuff i didn’t solve 

and i want you to check all my work

-uncalibrated thermometer used throughout for all temp. readings

Part A Simple Distillation

Appearance of Impure cyclohexanol? -clear and colorless liquid

Amt weighed/measured = 20.0 mL

Appearance of forerun = clear/colorless solution

Volume of forerun = 6.2 mL

Obs. bp range for forerun = 78 C – 138C (first drop at 78C)

Appearance of product = clear/colorless solution

Yield of final purified cyclohexanol = 13 mL

Obs. bp range of final purified cyclohexanol = 140 C – 155 C

bp of final purified cyclohexanol = 155 C (observed temp at which bp was constant

distillation rate = 1 drop per second, slowing to 1 drop per 3 sec towards the end

Part B Fractional Distillation

Appearance of 50:50 cyclohexene/toluene mixture? -clear and colorless liquid

Amt weighed/measured = 25.0 mL

Appearance of forerun = clear/colorless solution

Volume of forerun = 0.0 mL (no forerun collected)

Obs. bp range for forerun = NA

Appearance of Fraction 1 = clear/colorless solution

Yield of Fraction 1 = 7.3 mL

bp range of Fraction 1= 77 C-83 C

distillation rate = 1 drop per second

Appearance of Fraction 2 = clear/colorless solution

Yield of Fraction 2 = 10.3 mL

Obs. bp range of Fraction 2= 83 C -97 C

distillation rate = 1 drop per second

Appearance of Fraction 3 = clear/colorless solution

Yield of Fraction 3 = 5.5 mL

Obs. bp range of Fraction 3= 97 C -110 C

distillation rate = 1 drop per second

Appearance of Residual in Distilling Flask = clear/colorless solution

Yield of Residual= ~2.0 mL

**the biggest thing to remember to do for this experiment is to do the Barometric Pressure

temperature correction on all your observed boiling point readings. The equation for correcting

the boiling point of a solution is:

corr.bp(C) = obs.bp(C) + ((760 mmHg -obs.BP mmHg)/10 mmHg) x 0.5 C)

where:

corr. = corrected

bp = boiling point

C = degrees Celsius

obs. = observed

BP = barometric pressure, in mm Hg (760 mmHg or torr = sea level pressure)

i.e., “for every 10 mmHg below 760 the BP is, you must correct by adding 0.5 C to the observed

bp.” So for instance, if the observed BP was 700 mmHg, this is 6 x 10 mmHg below 760, and

therefore you must add 6 x 0.5 C, or 3 C to the observed bp.

You need to do the correction for both the lower and upper limit of the bp range (it is the same

number that is added or subtracted from the observed value for both limits).

Please note that you may have any additional number for the actual bp. e.g., for cyclohexanol in

Part A of Exp.3, you may also have observed a particular temperature that was fairly constant

towards the end of the distillation…this is the boiling pt of cyclohexanol and it also needs to be

barom. press. corrected.