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Organic Chemistry: For PROPANE (CH3CH2CH3)

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Organic Chemistry:For PROPANE (CH3CH2CH3) RATIO: yield secondary Hydrogen/yield of primary hydrogen = 2/6 *4.5 = 1.5 therefore secondary:primary ration = 1.5:160% Secondary product & 40% primary productMy question is – The percentages above (60% & 40%) how do we calculate these???

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At a particular temperature and pressure 20.0 g of CO2 occupy 7.16 liters
Part A K and H S O 4 Express your answer as a chemical
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