Organic Chemistry: For PROPANE (CH3CH2CH3)

Organic Chemistry:For PROPANE (CH3CH2CH3) RATIO: yield secondary Hydrogen/yield of primary hydrogen = 2/6 *4.5 = 1.5 therefore secondary:primary ration = 1.5:160% Secondary product & 40% primary productMy question is – The percentages above (60% & 40%) how do we calculate these???