The heat gained by the ice melted the ice and raised the temperature of the melted ice from itsinitial temperature to the final temperature of the water in the calorimeter.Use this information to calculate the heat of fusion per gram of ice for each trial.Here is one trial.Initial mass of water : 50.51 gInitial Temperature of water: 21.8 CFinal Temperature of water: 10.9 CMass of ice: 10.24 gMass of water ice: 60.75 gSpecific heat capacity of water: 4.184 J/g CAverage heat capacity of calorimeter: 93.4 JI’m having a really hard time figuring out the heat of fusion.I’ve tried a lot of different equations and I just can’t seem to be able to find the right answer.