2.50 mol NOCl was placed in a 2.50 L reaction vessel at 400ºC. After equilibrium was established it was found that 28% of the NOCl had dissociated according to the equation2NOCl(g) 2NO(g) Cl2(g).Calculate the equilibrium constant Kc for the reaction.Step 1: 2.50mol / 2.50L = 1.0MStep 2: 1.0-28%=0.72After that I’m not sure what to do.
